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JEE Main 2026 · 4 Apr · Shift 2, Chemistry question 52

The species having identical radii according to the Bohr's theory are:

A. H (first orbit)

B. HeX+\ce{He+} (first orbit)

C. HeX+\ce{He+} (Second orbit)

D. LiX2+\ce{Li^{2+}} (first orbit)

E. BeX3+\ce{Be^{3+}} (Second orbit)

Choose the correct answer from the options given below:

Choose one option
Answer and worked solution

Official answer: B

Bohr radius r∝n2Zr\propto\frac{n^2}Z:

Species n2/Zn^2/Z
A: H, n = 1 1
B: He⁺, n = 1 ½
C: He⁺, n = 2 2
D: Li²⁺, n = 1 ⅓
E: Be³⁺, n = 2 1

Equal: A and E.

(B)

Topics:Bohr model
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