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JEE Main 2026 · 4 Apr · Shift 1, Physics question 43

The voltage and the current between AA and BB points shown in the circuit are ________.

Between a left vertical wire (A at its bottom) and a right vertical wire (B partway up), four branches are in parallel, each with 27 V of emf and 3 Ω: three branches have a 27 V cell and a 3 Ω resistor, one has 14 V and 13 V cells in series with a 3 Ω resistor. A diagonal wire from A to B contains two 3 Ω resistors in series.
Choose one option
Answer and worked solution

Official answer: B

Four sources in parallel. Each branch is 27 V with 3 Ω (14 V + 13 V counts as 27 V), equivalent to 27 V with 34\frac34 Ω.

Load. The A-B wire has 3+3=63+3=6 Ω, so
I=276.75=4 A,VAB=4×6=24 V.I=\frac{27}{6.75}=4\text{ A},\qquad V_{AB}=4\times6=24\text{ V}.

(B)

Topics:EMF and internal resistanceKirchhoff's laws
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