JEE Main 2026 · 4 Apr · Shift 1 · Physics Q26

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PhysicsSingle correct+4 / -1Question 26 of 75

In a screw gauge when the circular scale is given five complete rotations it moves linearly by 2.5 mm. If the circular scale has 100 divisions, the least count of screw gauge is ________ mm.

1\times10^{-2}

1\times10^{-3}

5\times10^{-2}

5\times10^{-3}

Answer and worked solution

Official answer: D

Pitch. Five rotations move 2.5 mm, so the pitch is 0.5 mm.

Least count. $\frac{0.5}{100}=5\times10^{-3}$ mm.

(D)

Topics:Vernier callipers and screw gauge Least count

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JEE Main 2026 · 4 Apr · Shift 1, Physics question 26