JEE Main 2026 · 4 Apr · Shift 1 · Chemistry Q59

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ChemistrySingle correct+4 / -1Question 59 of 75

Given below are two statements:

Statement I: The covalency of oxygen is generally two but it can exceed upto four. The oxidation state of oxygen in $\ce{SO2}$ is −2 and in $\ce{OF2}$ it is +2.

Statement II: The anomalous behaviour of oxygen when compared to the other elements of group 16 is due to its small size and high electronegativity.

In the light of the above statements, choose the correct answer from the options given below

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is true but Statement II is false

Statement I is false but Statement II is true

Answer and worked solution

Official answer: A

Statement I. Oxygen usually forms two bonds but can reach four (e.g. in some oxides). It is −2 in $\ce{SO2}$ and +2 in $\ce{OF2}$ , since F is more electronegative: true.

Statement II. Oxygen's anomalous behaviour comes from its small size, high electronegativity and lack of d orbitals: true.

(A)

Topics:Group 16 Oxidation number

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JEE Main 2026 · 4 Apr · Shift 1, Chemistry question 59