JEE Main 2026 · 4 Apr · Shift 1 · Chemistry Q56

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ChemistrySingle correct+4 / -1Question 56 of 75

In order to oxidise a mixture of 1 mole each of $\ce{FeC2O4}$ , $\ce{Fe2(C2O4)3}$ , $\ce{FeSO4}$ and $\ce{Fe2(SO4)3}$ in acidic medium, the number of moles of $\ce{KMnO4}$ required is

Answer and worked solution

Official answer: B

Electrons released (acid medium):

$\ce{FeC2O4}$ : Fe²⁺ → Fe³⁺ (1) and $\ce{C2O4^{2-}}$ → 2CO₂ (2): 3.
$\ce{Fe2(C2O4)3}$ : three oxalates: 6.
$\ce{FeSO4}$ : 1.
$\ce{Fe2(SO4)3}$ : 0.

Total 10 electrons. Each $\ce{MnO4-}$ takes 5, so 2 mol $\ce{KMnO4}$ .

(B)

Topics:Redox titrations Important compounds (KMnO4, K2Cr2O7)

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JEE Main 2026 · 4 Apr · Shift 1, Chemistry question 56