Skip to content
dronacharya.ai
← JEE Main 2026 · 2 Apr · Shift 2
PhysicsInteger+4 / -1Question 48 of 75

JEE Main 2026 · 2 Apr · Shift 2, Physics question 48

5 moles of unknown gas is heated at constant volume from 10 °C to 20 °C. The molar specific heat of this gas at constant pressure cp=8c_p=8 cal/mol.°C and R=8.36R=8.36 J/mol.°C. The change in the internal energy of the gas is ________ calorie.

Answer and worked solution

Official answer: 300

Heat capacity at constant volume. R=8.364.18=2R=\frac{8.36}{4.18}=2 cal/mol °C, so cv=cp−R=6c_v=c_p-R=6 cal/mol °C.

Internal energy. ΔU=ncvΔT=5×6×10=300\Delta U=nc_v\Delta T=5\times6\times10=300 cal.

Answer: 300