JEE Main 2026 · 2 Apr · Shift 2 · Physics Q45

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PhysicsSingle correct+4 / -1Question 45 of 75

The equation of motion of a particle is given by $x=a\sin\left(50t+\pi/3\right)$ cm. The particle will come to rest at time $t_1$ and it will have zero acceleration at time $t_2$ . The $t_1$ and $t_2$ respectively are ________.

\dfrac\pi{300}

\dfrac\pi{75}

\dfrac\pi{75}

\dfrac\pi{300}

\dfrac\pi{300}

\dfrac\pi{25}

\dfrac\pi{50}

\dfrac\pi{100}

Answer and worked solution

Official answer: A

At rest when $v\propto\cos(50t+\frac\pi3)=0$ : $50t+\frac\pi3=\frac\pi2$ , so $t_1=\frac\pi{300}$ s.

Zero acceleration when $\sin(50t+\frac\pi3)=0$ : $50t+\frac\pi3=\pi$ , so $t_2=\frac{2\pi/3}{50}=\frac\pi{75}$ s.

(A)

Topics:Simple harmonic motion

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JEE Main 2026 · 2 Apr · Shift 2, Physics question 45