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← JEE Main 2026 · 2 Apr · Shift 2
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JEE Main 2026 · 2 Apr · Shift 2, Mathematics question 8

A man throws a fair coin repeatedly. He gets 10 points for each head he throws and 5 points for each tail he throws. If the probability that he gets exactly 30 points is mn\dfrac mn, gcd⁡(m,n)=1\gcd(m,n)=1, then m+nm+n is equal to :

Choose one option
Answer and worked solution

Official answer: C

Units of 5 points. A head adds 2 and a tail adds 1, each with probability ½. Let pkp_k be the probability that the running total ever equals exactly kk.

Recursion. pk=12pk−1+12pk−2p_k=\frac12p_{k-1}+\frac12p_{k-2} with p0=1p_0=1, p1=12p_1=\frac12:
p2=34, p3=58, p4=1116, p5=2132, p6=4364.p_2=\tfrac34,\ p_3=\tfrac58,\ p_4=\tfrac{11}{16},\ p_5=\tfrac{21}{32},\ p_6=\tfrac{43}{64}.

Answer. 30 points is k=6k=6: 4364\frac{43}{64}, so m+n=107m+n=107.

(C)