JEE Main 2026 · 2 Apr · Shift 2, Mathematics question 3

Infinitely many solutions: the third equation must be a combination $p\,(\text{eq}_1)+q\,(\text{eq}_2)$.

Match coefficients. From $x$ and $y$: $p+2q=1$ and $5p+3q=6$, so $p=\frac97$, $q=-\frac17$.

Then $a=6p+4q=\frac{50}7$ and $b=4p+7q=\frac{29}7$, so $a-b=3$: $(a,b)$ lies on $x-y=3$.

(B)