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JEE Main 2026 · 2 Apr · Shift 2, Chemistry question 62

Complete combustion of X g of an organic compound gave 0.25 g of COX2\ce{CO2} and 0.12 g of HX2O\ce{H2O}. If the % of carbon is 25% and of hydrogen is 4.89%, then X = ________ ×10−3\times10^{-3} g. (Nearest integer)
(Molar mass of C, H and O are 12, 1 and 16 g mol−1^{-1} respectively.)

Choose one option
Answer and worked solution

Official answer: A

Mass of carbon. 0.25×1244=0.06820.25\times\frac{12}{44}=0.0682 g, which is 25% of X.

X. X=0.273X=0.273 g =273×10−3=273\times10^{-3} g.

Check with hydrogen. 0.12×218=0.01330.12\times\frac2{18}=0.0133 g, and 0.01330.273=4.89%\frac{0.0133}{0.273}=4.89\% ✓.

(A)

Topics:Qualitative and quantitative analysis of organic compounds
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