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JEE Main 2026 · 2 Apr · Shift 2, Chemistry question 60

Given below are two statements :

Statement I : Among Zn, Mn, Sc and Cu, the energy required to remove the third valence electron is highest for Zn and lowest for Sc.

Statement II : The correct order of the following complexes in terms of CFSE is [Co(HX2O)X6]X2+<[Co(HX2O)X6]X3+<[Co(en)X3]X3+\ce{[Co(H2O)6]^{2+}} < \ce{[Co(H2O)6]^{3+}} < \ce{[Co(en)3]^{3+}}.

In the light of the above statements, choose the correct answer from the options given below :

Choose one option
Answer and worked solution

Official answer: A

Statement I. Third ionisation enthalpies: Sc 2389 (gives the noble-gas core, lowest), Mn 3248, Cu 3555, Zn 3833 (breaks into 3d103d^{10}, highest): true.

Statement II. CFSE:

  • [Co(HX2O)X6]X2+\ce{[Co(H2O)6]^{2+}}: high-spin d⁷, small;
  • [Co(HX2O)X6]X3+\ce{[Co(H2O)6]^{3+}}: low-spin d⁶, larger;
  • [Co(en)X3]X3+\ce{[Co(en)3]^{3+}}: low-spin d⁶ with the stronger ligand en, largest.

True.

(A)