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PhysicsInteger+4 / -1Question 49 of 75

JEE Main 2026 · 2 Apr · Shift 1, Physics question 49

A uniform wire of length ll of weight ww is suspended from the roof with a weight of WW at the other end. The stress in the wire at l3\dfrac l3 distance from the top is (WA+2γwA)\left(\dfrac WA+\dfrac2\gamma\dfrac wA\right), where, AA is the cross sectional area of the wire. The value of γ\gamma is ________.

Answer and worked solution

Official answer: 3

Load at l/3 from the top. The section supports WW plus the weight of the wire below it, 23w\frac23w.

Stress. WA+23⋅wA\dfrac WA+\dfrac23\cdot\dfrac wA, so 2γ=23\dfrac2\gamma=\dfrac23 and γ=3\gamma=3.

Answer: 3