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← JEE Main 2026 · 2 Apr · Shift 1
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JEE Main 2026 · 2 Apr · Shift 1, Physics question 35

The equation of a plane progressive wave is given by y=5cos⁡π(200t−x150)y=5\cos\pi\left(200t-\dfrac x{150}\right) where xx and yy are in cm and tt is in second. The velocity of the wave is ________ m/s.

Choose one option
Answer and worked solution

Official answer: D

Read off the wave. ω=200π\omega=200\pi rad/s and k=π150k=\dfrac\pi{150} cm⁻¹.

Speed. v=ωk=200×150=3×104v=\dfrac\omega k=200\times150=3\times10^4 cm/s =300=300 m/s.

(D)