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JEE Main 2026 · 2 Apr · Shift 1, Physics question 32

A parallel plate air capacitor has a capacitance CC. When it is half filled as show in figure with a dielectric constant K=5K=5, the percentage increase in the capacitance is ________.

Parallel-plate capacitor with plate separation d (top plate +, bottom plate −); a dielectric slab with K = 5 fills the upper half, thickness d/2, across the full plate area; the lower half is air.
Choose one option
Answer and worked solution

Official answer: B

Two capacitors in series. Each half has gap d/2d/2, so C1=Kϵ0Ad/2=10CC_1=\dfrac{K\epsilon_0A}{d/2}=10C and C2=ϵ0Ad/2=2CC_2=\dfrac{\epsilon_0A}{d/2}=2C.

Combination. C′=10C⋅2C12C=53CC'=\dfrac{10C\cdot2C}{12C}=\dfrac53C.

Increase. 23=66.67%\frac23=66.67\%.

(B)