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JEE Main 2026 · 2 Apr · Shift 1, Mathematics question 25

If α=∫023log⁡2(x2+4)dx+∫242x−4 dx\alpha=\displaystyle\int_0^{2\sqrt3}\log_2\left(x^2+4\right)dx+\int_2^4\sqrt{2^x-4}\,dx, then α2\alpha^2 is equal to ________.

Answer and worked solution

Official answer: 192

Inverse functions. f(x)=log⁡2(x2+4)f(x)=\log_2(x^2+4) increases on [0,23][0,2\sqrt3] from 2 to 4, and its inverse is f−1(y)=2y−4f^{-1}(y)=\sqrt{2^y-4} on [2,4][2,4].

Area identity.
∫023f+∫24f−1=23⋅f(23)−0⋅f(0)=83.\int_0^{2\sqrt3}f+\int_2^4f^{-1}=2\sqrt3\cdot f(2\sqrt3)-0\cdot f(0)=8\sqrt3.

Value. α2=192\alpha^2=192.

Answer: 192