JEE Main 2026 · 2 Apr · Shift 1 · Chemistry Q71

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ChemistryInteger+4 / -1Question 71 of 75

5.33 g of $\ce{CrCl3.6H2O}$ , which is a 1 : 3 electrolyte, is dissolved in water and is passed through a cation exchanger. The chloride ions in the eluted solution, on treatment with $\ce{AgNO3}$ results in 8.61 g of AgCl. The ratio of moles of complex reacted and moles of AgCl formed is ________ $\times10^{-2}$ . (Nearest integer)
[Molar mass in g mol $^{-1}$ Cr : 52, Ag : 108, Cl : 35.5, H : 1, O : 16]

Your answer

Answer and worked solution

Official answer: 33

Moles of complex. Molar mass of $\ce{CrCl3.6H2O}$ $=52+106.5+108=266.5$ , so 5.33 g is 0.02 mol.

Moles of AgCl. $\frac{8.61}{143.5}=0.06$ mol, i.e. 3 Cl⁻ per formula. This is consistent with the 1 : 3 electrolyte $\ce{[Cr(H2O)6]Cl3}$ : the cation exchanger replaces $\ce{[Cr(H2O)6]^{3+}}$ by $\ce{3H+}$ and all the chloride elutes.

Ratio. $\frac{0.02}{0.06}=0.333=33\times10^{-2}$ .

Answer: 33

Topics:Nomenclature Stoichiometry

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JEE Main 2026 · 2 Apr · Shift 1, Chemistry question 71