JEE Main 2026 · 2 Apr · Shift 1 · Chemistry Q51

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ChemistrySingle correct+4 / -1Question 51 of 75

The mass of iron converted into $\ce{Fe3O4}$ by the action of 18 g of steam is :
(Given : Molar mass of H, O and Fe are 1, 16 and 56 g mol $^{-1}$ respectively)
Assume iron is present in excess :

2.1 g

4.2 g

21 g

42 g

Answer and worked solution

Official answer: D

Reaction. $\ce{3Fe + 4H2O -> Fe3O4 + 4H2}$ .

Moles. 18 g steam = 1 mol, which reacts with $\frac34$ mol Fe $=\frac34\times56=42$ g.

(D)

Topics:Stoichiometry

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JEE Main 2026 · 2 Apr · Shift 1, Chemistry question 51