JEE Main 2022 · 30 Jul · Shift 2 · Physics Q30

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PhysicsInteger+4 / -1Question 30 of 90

Two projectiles are thrown towards each other at 15° and 45° angles respectively with the horizontal at the same speed. The difference between the horizontal distances traveled by the two projectiles is 80 m. The initial speed of the projectiles is _______ m s $^{-1}$ [Given g = 10 m s $^{-2}$ ]

Your answer

Answer and worked solution

Official answer: 40

Ranges $\frac{u^2\sin30°}g=\frac{u^2}{20}$ and $\frac{u^2}{10}$ . Difference $\frac{u^2}{20}=80$ , so $u=40$ m/s.

Answer: 40

Topics:Projectile motion

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JEE Main 2022 · 30 Jul · Shift 2, Physics question 30