JEE Main 2022 · 30 Jul · Shift 2 · Physics Q14

← JEE Main 2022 · 30 Jul · Shift 2

PhysicsSingle correct+4 / -1Question 14 of 90

Two poloroids P $_1$ and P $_2$ are placed parallel to each other with common axis. The light of intensity I $_0$ passes through a polaroid sheet P $_1$ and then passes through polaroid P $_2$ . If P $_2$ is now rotated by 60°, then the intensity of the output light from P $_2$ will be:

\dfrac{I_0}2

\dfrac{I_0}4

Zero

\dfrac{I_0}8

Answer and worked solution

Official answer: D

Unpolarised light of intensity $I_0$ leaves $P_1$ at $\frac{I_0}2$ ; with the axes 60° apart, $P_2$ passes $\frac{I_0}2\cos^260°=\frac{I_0}8$ .

(D)

Topics:Polarisation and Brewster's law

← Previous question Next question →

JEE Main 2022 · 30 Jul · Shift 2, Physics question 14