JEE Main 2022 · 30 Jul · Shift 2 · Physics Q9

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PhysicsSingle correct+4 / -1Question 9 of 90

An oscillating simple pendulum of time period T $_o$ is placed in a lift which is accelerating upwards with 2.5 m/s $^2$ . The time period of pendulum in the lift will be (if g = 10 m/s $^2$ )

T_o

\dfrac2{\sqrt5}T_o

\dfrac2{\sqrt3}T_o

\dfrac{T_o}4

Answer and worked solution

Official answer: B

Effective g $=12.5$ m/s²: $T=T_o\sqrt{\frac{10}{12.5}}=\frac2{\sqrt5}T_o$ .

(B)

Topics:Simple and compound pendulum Pseudo forces and non-inertial frames

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JEE Main 2022 · 30 Jul · Shift 2, Physics question 9