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← JEE Main 2022 · 30 Jul · Shift 2
PhysicsSingle correct+4 / -1Question 4 of 90

JEE Main 2022 · 30 Jul · Shift 2, Physics question 4

A mass of 0.5 kg is attached to one end of a massless spring whose natural length is 1 m and spring constant is 800 N/m. The other end of the spring is fixed while the mass moves in a circular path in a horizontal plane with an angular speed of 20 rad/s. The extension in the length of the spring will be :

Choose one option
Answer and worked solution

Official answer: C

Spring supplies centripetal force. kx=mω2(1+x)kx=m\omega^2(1+x): 800x=200(1+x)800x=200(1+x), so x=13x=\frac13 m.

(C)