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← JEE Main 2022 · 30 Jul · Shift 2
MathematicsInteger+4 / -1Question 87 of 90

JEE Main 2022 · 30 Jul · Shift 2, Mathematics question 87

Let L1_1 be a line in the yz - plane with y and z intercepts 14\dfrac14 and 1C\dfrac1C (C > 0) respectively. Let L2_2 be the line in the xz - plane with x and z intercepts 13\dfrac13 and −1C-\dfrac1C respectively. If the shortest distance between L1_1 and L2_2 is 15\dfrac15, then C2^2 is equal to _______.

Answer and worked solution

Official answer: 75

Lines. L1L_1 through (0,14,0)\left(0,\frac14,0\right) with direction (0,−14,1C)\left(0,-\frac14,\frac1C\right); L2L_2 through (13,0,0)\left(\frac13,0,0\right) with direction (−13,0,−1C)\left(-\frac13,0,-\frac1C\right).

Scaled directions (0,−C,4)(0,-C,4) and (−C,0,−3)(-C,0,-3), with cross product (3C,−4C,−C2)(3C,-4C,-C^2) of length CC2+25C\sqrt{C^2+25}. Joining vector (13,−14,0)\left(\frac13,-\frac14,0\right) gives dot product 2C2C.

Distance 2C2+25=15\dfrac2{\sqrt{C^2+25}}=\dfrac15, so C2=75C^2=75.

Answer: 75

Topics:Skew lines