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← JEE Main 2022 · 30 Jul · Shift 2
MathematicsInteger+4 / -1Question 85 of 90

JEE Main 2022 · 30 Jul · Shift 2, Mathematics question 85

If the area enclosed by the curves y=x2y=x^2, y3=xy^3=x, x=−1x=-1 and y=x2y=x^2, y3=xy^3=x, x=1x=1, above the line x=2yx=2y is nn+1\dfrac n{n+1}, then n is equal to _______.

Answer and worked solution

Official answer: 47

Total between y=x2y=x^2 and y=x1/3y=x^{1/3}: 1312\frac{13}{12} on [−1,0][-1,0] and 512\frac5{12} on [0,1][0,1], 1.5 in all.

Below y=x2y=\frac x2 we lose ∫01/2(x2−x2)dx=148\int_0^{1/2}\left(\frac x2-x^2\right)dx=\frac1{48} and ∫−10(x2−x1/3)dx=12\int_{-1}^0\left(\frac x2-x^{1/3}\right)dx=\frac12.

Area 1.5−12−148=47481.5-\frac12-\frac1{48}=\frac{47}{48}, so n=47n=47.

Answer: 47