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← JEE Main 2022 · 30 Jul · Shift 2
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JEE Main 2022 · 30 Jul · Shift 2, Mathematics question 82

If p1p_1 and p2p_2, respectively, are the second largest and the fourth largest prime numbers in the factorization of the coefficient of x30x^{30} in the expression of (x2+2+1x2)−5(1+x2)40\left(x^2+2+\dfrac1{x^2}\right)^{-5}(1+x^2)^{40}, then p1+p2p_1+p_2 is equal to _______

Answer and worked solution

Official answer: 34

Simplify. x2+2+1x2=(1+x2)2x2x^2+2+\frac1{x^2}=\frac{(1+x^2)^2}{x^2}, so the expression is x10(1+x2)30x^{10}(1+x^2)^{30} and the coefficient of x30x^{30} is (3010)=30045015=32⋅5⋅7⋅11⋅13⋅23⋅29\binom{30}{10}=30045015=3^2\cdot5\cdot7\cdot11\cdot13\cdot23\cdot29.

Primes in decreasing order 29, 23, 13, 11: p1+p2=23+11=34p_1+p_2=23+11=34.

Answer: 34