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← JEE Main 2022 · 30 Jul · Shift 2
MathematicsSingle correct+4 / -1Question 63 of 90

JEE Main 2022 · 30 Jul · Shift 2, Mathematics question 63

If the system of linear equations

λx+y−z=−1\lambda x+y-z=-1
x−y−3z=2x-y-3z=2
−x+y+z=μ-x+y+z=\mu

has infinitely many solutions, then the equation of the line passing through the points (λ+2μ, 2λ+μ)(\lambda+2\mu,\ 2\lambda+\mu) and (1, λμ)(1,\ \lambda\mu) is

Choose one option
Answer and worked solution

Official answer: C

Singular. det⁡=2λ+2=0\det=2\lambda+2=0 gives λ=−1\lambda=-1. Then row 3 =12=\frac12(row 1) −12-\frac12(row 2) needs μ=−12−1=−32\mu=-\frac12-1=-\frac32.

Points (−4,−72)\left(-4,-\frac72\right) and (1,32)\left(1,\frac32\right): slope 1, line 2x−2y=−12x-2y=-1.

(C)