JEE Main 2022 · 30 Jul · Shift 2 · Chemistry Q32

ChemistrySingle correct+4 / -1Question 32 of 90

When the kinetic energy of an electron is increased nine times, the wavelength of the de-Broglie wave associated with it would become :

One-third

Three times

Two third

One sixth

Answer and worked solution

Official answer: A

de Broglie $\lambda=\dfrac h{\sqrt{2mK}}$ : nine times the energy gives one-third the wavelength.

(A)

Topics:de Broglie and Heisenberg

JEE Main 2022 · 30 Jul · Shift 2, Chemistry question 32