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← JEE Main 2022 · 29 Jul · Shift 2
PhysicsInteger+4 / -1Question 56 of 90

JEE Main 2022 · 29 Jul · Shift 2, Physics question 56

The speed of a transverse wave passing through a string of length 50 cm and mass 10 g is 60 m s−1^{-1}. The area of cross-section of the wire is 2.0 mm2^2 and its Young's modulus is 1.2×10111.2\times10^{11} N m−2^{-2}. The extension of the wire over its natural length due to its tension will be x×10−5x\times10^{-5} m. The value of xx is _______.

Answer and worked solution

Official answer: 15

Tension T=μv2=0.02×3600=72T=\mu v^2=0.02\times3600=72 N.

Extension TLAY=72×0.52×10−6×1.2×1011=1.5×10−4\dfrac{TL}{AY}=\dfrac{72\times0.5}{2\times10^{-6}\times1.2\times10^{11}}=1.5\times10^{-4} m =15×10−5=15\times10^{-5}.

Answer: 15