JEE Main 2022 · 29 Jul · Shift 2 · Physics Q47

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PhysicsSingle correct+4 / -1Question 47 of 90

A thermodynamic system is taken from an original state D to an intermediate state E by the linear process shown in the figure. Its volume is then reduced to the original volume from E to F by an isobaric process. The total work done by the gas from D to E to F will be

P-V diagram: D at (2.0 m³, 600 N/m²) joined by a straight line to E at (5.0 m³, 300 N/m²), then isobaric back to F at (2.0 m³, 300 N/m²).

−450 J

450 J

900 J

1350 J

Answer and worked solution

Official answer: B

Cycle area. D → E → F is clockwise and closes back at D's volume, so the work is the triangle's area: $\frac12\times3\times300=450$ J.

(B)

Topics:Work done by a gas

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JEE Main 2022 · 29 Jul · Shift 2, Physics question 47