JEE Main 2022 · 29 Jul · Shift 2 · Physics Q40

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PhysicsSingle correct+4 / -1Question 40 of 90

An α particle and a proton are accelerated from rest through the same potential difference. The ratio of linear momenta acquired by above two particals will be:

\sqrt2:1

2\sqrt2:1

4\sqrt2:1

8:1

Answer and worked solution

Official answer: B

Momentum $p=\sqrt{2mqV}$ : $\dfrac{p_\alpha}{p_p}=\sqrt{4\times2}=2\sqrt2$ .

(B)

Topics:de Broglie waves

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JEE Main 2022 · 29 Jul · Shift 2, Physics question 40