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← JEE Main 2022 · 29 Jul · Shift 2
MathematicsInteger+4 / -1Question 26 of 90

JEE Main 2022 · 29 Jul · Shift 2, Mathematics question 26

If [t] denotes the greatest integer ≤ t, then the number of points, at which the function f(x)=4∣2x+3∣+9[x+12]−12[x+20]f(x)=4|2x+3|+9\left[x+\dfrac12\right]-12[x+20] is not differentiable in the open interval (−20, 20), is _______.

Answer and worked solution

Official answer: 79

Jumps. [x+20]=[x]+20[x+20]=[x]+20, so f=4∣2x+3∣+9[x+12]−12[x]−240f=4|2x+3|+9\left[x+\frac12\right]-12[x]-240. The first floor jumps at the 40 half-integers in (−20, 20), the second at the 39 integers; they never cancel. The corner of ∣2x+3∣|2x+3| at −32-\frac32 is one of the half-integers.

Total 79.

Answer: 79