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← JEE Main 2022 · 29 Jul · Shift 2
MathematicsInteger+4 / -1Question 21 of 90

JEE Main 2022 · 29 Jul · Shift 2, Mathematics question 21

The sum and product of the mean and variance of a binomial distribution are 82.5 and 1350 respectively. Then the number of trials in the binomial distribution is _______.

Answer and worked solution

Official answer: 96

Mean and variance are roots of t2−82.5t+1350=0t^2-82.5t+1350=0: 60 and 22.5. So np=60np=60, q=22.560=38q=\frac{22.5}{60}=\frac38, p=58p=\frac58, n=96n=96.

Answer: 96