JEE Main 2022 · 29 Jul · Shift 2 · Mathematics Q19

MathematicsSingle correct+4 / -1Question 19 of 90

The domain of the function $f(x)=\sin^{-1}\left(\dfrac{x^2-3x+2}{x^2+2x+7}\right)$ is :

[1,\infty)

[-1,2]

[-1,\infty)

(-\infty,2]

Answer and worked solution

Official answer: C

Upper bound. $x^2-3x+2\le x^2+2x+7$ gives $x\ge-1$ . Lower bound $2x^2-x+9\ge0$ always holds (the denominator is always positive).

(C)

Topics:Domain and range Inverse trigonometric functions

JEE Main 2022 · 29 Jul · Shift 2, Mathematics question 19