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← JEE Main 2022 · 29 Jul · Shift 2
MathematicsSingle correct+4 / -1Question 3 of 90

JEE Main 2022 · 29 Jul · Shift 2, Mathematics question 3

If the system of equations

x+y+z=6x+y+z=6
2x+5y+αz=β2x+5y+\alpha z=\beta
x+2y+3z=14x+2y+3z=14

has infinitely many solutions, then α + β is equal to

Choose one option
Answer and worked solution

Official answer: C

Dependence. Row 2 must equal a(row 1)+b(row 3)a(\text{row }1)+b(\text{row }3): a+b=2a+b=2, a+2b=5a+2b=5 give a=−1a=-1, b=3b=3.

So α=−1+9=8\alpha=-1+9=8, β=−6+42=36\beta=-6+42=36, and α+β=44\alpha+\beta=44.

(C)