Given below are two statements.
Statement I: The compound (A) shown, a carbon bearing NO, H, a (Z)-prop-1-enyl group and an (E)-prop-1-enyl group, is optically active.
Statement II: The second compound shown is mirror image of above compound A.
In the light of the above statement, choose the most appropriate answer from the options given below.
Official answer: C
Statement I. The central carbon bears H, NO₂, a cis-propenyl and a trans-propenyl group: four different groups, so the compound is chiral and optically active.
Statement II. In the second drawing the cis and trans propenyl groups have not swapped the way a reflection requires; reading the wedges, it is the same configuration as A (an identical molecule), not its mirror image. So II is incorrect.
(C)