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← JEE Main 2022 · 29 Jul · Shift 1
PhysicsInteger+4 / -1Question 60 of 90

JEE Main 2022 · 29 Jul · Shift 1, Physics question 60

If the potential barrier across a p-n junction is 0.6 V. Then the electric field intensity, in the depletion region having the width of 6×10−66\times10^{-6} m, will be _______ ×105\times10^5 N/C.

Answer and worked solution

Official answer: 1

Field 0.66×10−6=1×105\dfrac{0.6}{6\times10^{-6}}=1\times10^5 N/C.

Answer: 1