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← JEE Main 2022 · 29 Jul · Shift 1
PhysicsInteger+4 / -1Question 56 of 90

JEE Main 2022 · 29 Jul · Shift 1, Physics question 56

A closely wounded circular coil of radius 5 cm produces a magnetic field of 37.68×10−437.68\times10^{-4} T at its center. The current through the coil is _______ A.

[Given, number of turns in the coil is 100 and π = 3.14]

Answer and worked solution

Official answer: 3

Coil centre. B=μ0NI2rB=\dfrac{\mu_0NI}{2r}, so I=2×0.05×37.68×10−44π×10−7×100=3I=\dfrac{2\times0.05\times37.68\times10^{-4}}{4\pi\times10^{-7}\times100}=3 A.

Answer: 3