JEE Main 2022 · 29 Jul · Shift 1 · Physics Q48 · Dronacharya Exams

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PhysicsSingle correct+4 / -1Question 48 of 90

Find the modulation index of an AM wave having 8 V variation where maximum amplitude of the AM wave is 9 V.

A

0.8

B

0.5

C

0.2

D

0.1

Answer and worked solution

Official answer: A

Extremes. $A_{max}=9$ V and $A_{max}-A_{min}=8$ V give $A_{min}=1$ V.

Index $\dfrac{9-1}{9+1}=0.8$ .

(A)

Topics:Modulation

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