JEE Main 2022 · 29 Jul · Shift 1 · Physics Q39

← JEE Main 2022 · 29 Jul · Shift 1

PhysicsSingle correct+4 / -1Question 39 of 90

The time period of oscillation of a simple pendulum of length L suspended from the roof of a vehicle, which moves without friction down an inclined plane of inclination α, is given by :

2\pi\sqrt{L/(g\cos\alpha)}

2\pi\sqrt{L/(g\sin\alpha)}

2\pi\sqrt{L/g}

2\pi\sqrt{L/(g\tan\alpha)}

Answer and worked solution

Official answer: A

Effective gravity. In the frame accelerating at $g\sin\alpha$ down the slope, the pseudo force cancels the along-slope part of gravity, leaving $g\cos\alpha$ normal to the incline. $T=2\pi\sqrt{L/(g\cos\alpha)}$ .

(A)

Topics:Simple and compound pendulum Pseudo forces and non-inertial frames

← Previous question Next question →

JEE Main 2022 · 29 Jul · Shift 1, Physics question 39