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← JEE Main 2022 · 29 Jul · Shift 1
MathematicsInteger+4 / -1Question 24 of 90

JEE Main 2022 · 29 Jul · Shift 1, Mathematics question 24

Let a1,a2,a3,…a_1,a_2,a_3,\dots be an A.P. If ∑r=1∞ar2r=4\displaystyle\sum_{r=1}^\infty\frac{a_r}{2^r}=4, then 4a24a_2 is equal to _______.

Answer and worked solution

Official answer: 16

Sum. With ar=a+(r−1)da_r=a+(r-1)d: ∑a2r=a\sum\frac a{2^r}=a and ∑(r−1)d2r=d\sum\frac{(r-1)d}{2^r}=d. So a+d=a2=4a+d=a_2=4.

Answer: 16