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← JEE Main 2022 · 29 Jul · Shift 1
ChemistryInteger+4 / -1Question 87 of 90

JEE Main 2022 · 29 Jul · Shift 1, Chemistry question 87

The reaction between X and Y is first order with respect to X and zero order with respect to Y.

Experiment [X] / mol L−1^{-1} [Y] / mol L−1^{-1} Initial rate / mol L−1^{-1} min−1^{-1}
I 0.1 0.1 2×10−32\times10^{-3}
II L 0.2 4×10−34\times10^{-3}
III 0.4 0.4 M×10−3M\times10^{-3}
IV 0.1 0.2 2×10−32\times10^{-3}

Examine the data of table and calculate ratio of numerical values of M and L. (Nearest Integer)

Answer and worked solution

Official answer: 40

Rate law rate =k[X]=k[X] with k=2×10−30.1=2×10−2k=\frac{2\times10^{-3}}{0.1}=2\times10^{-2} min⁻¹.

Unknowns. L=4×10−3k=0.2L=\frac{4\times10^{-3}}{k}=0.2; M×10−3=k×0.4=8×10−3M\times10^{-3}=k\times0.4=8\times10^{-3}, M=8M=8. Ratio 80.2=40\frac{8}{0.2}=40.

Answer: 40