JEE Main 2022 · 29 Jul · Shift 1 · Chemistry Q66

← JEE Main 2022 · 29 Jul · Shift 1

ChemistrySingle correct+4 / -1Question 66 of 90

The reaction of zinc with excess of aqueous alkali, evolves hydrogen gas and gives :

\mathrm{Zn(OH)_2}

ZnO

\mathrm{[Zn(OH)_4]^{2-}}

\mathrm{[ZnO_2]^{2-}}

Answer and worked solution

Official answer: D

Reaction. $\mathrm{Zn+2NaOH\to Na_2ZnO_2+H_2}$ : sodium zincate, written $\mathrm{[ZnO_2]^{2-}}$ in the NCERT form (in solution it is $\mathrm{[Zn(OH)_4]^{2-}}$ ).

(D)

Topics:Transition element properties

← Previous question Next question →

JEE Main 2022 · 29 Jul · Shift 1, Chemistry question 66