JEE Main 2022 · 29 Jul · Shift 1 · Chemistry Q62

ChemistrySingle correct+4 / -1Question 62 of 90

$\mathrm{N_{2(g)}+3H_{2(g)}\rightleftharpoons2NH_{3(g)}}$
20 g 5 g

Consider the above reaction, the limiting reagent of the reaction and number of moles of NH $_3$ formed respectivly are :

\mathrm{H_2}

, 1.42 moles

\mathrm{H_2}

, 0.71 moles

\mathrm{N_2}

, 1.42 moles

\mathrm{N_2}

, 0.71 moles

Answer and worked solution

Official answer: C

Moles. $\mathrm{N_2}$ : $\frac{20}{28}=0.714$ ; $\mathrm{H_2}$ : 2.5, more than the 2.14 needed. $\mathrm{N_2}$ limits.

Ammonia $2\times0.714\approx1.42$ mol.

(C)

Topics:Stoichiometry

JEE Main 2022 · 29 Jul · Shift 1, Chemistry question 62