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← JEE Main 2022 · 28 Jul · Shift 2
PhysicsInteger+4 / -1Question 30 of 90

JEE Main 2022 · 28 Jul · Shift 2, Physics question 30

In an experiment to find acceleration due to gravity (g) using simple pendulum, time period of 0.5 s is measured from time of 100 oscillation with a watch of 1 s resolution. If measured value of length is 10 cm known to 1 mm accuracy, The accuracy in the determination of g is found to be xx%. The value of xx is ______.

Answer and worked solution

Official answer: 5

Errors. Δgg=Δll+2ΔTT=0.110+2×150=0.05\frac{\Delta g}g=\frac{\Delta l}l+2\frac{\Delta T}T=\frac{0.1}{10}+2\times\frac1{50}=0.05.

Answer: 5