JEE Main 2022 · 28 Jul · Shift 2 · Physics Q19 · Dronacharya Exams

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PhysicsSingle correct+4 / -1Question 19 of 90

An n.p.n transistor with current gain β = 100 in common emitter configuration is shown in figure. The output voltage of the amplifier will be

Common-emitter npn amplifier: a 1 mV AC source through capacitor C and a 1 kΩ base resistor to the base; a 10 kΩ collector load to the supply; Vout taken from the collector through a coupling capacitor.

A

0.1 V

B

1.0 V

C

10 V

D

100 V

Answer and worked solution

Official answer: B

Voltage gain $\beta\frac{R_C}{R_B}=100\times10=1000$ , so $V_{out}=1$ V.

(B)

Topics:Transistors

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