JEE Main 2022 · 28 Jul · Shift 2 · Physics Q16

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PhysicsSingle correct+4 / -1Question 16 of 90

The power of a lens (biconvex) is 1.25 m $^{-1}$ in particular medium. Refractive index of the lens is 1.5 and radii of curvature are 20 cm and 40 cm respectively. The refractive index of surrounding medium:

1.0

\dfrac97

\dfrac32

\dfrac43

Answer and worked solution

Official answer: B

Lens maker. $1.25=\left(\frac{1.5}\mu-1\right)\left(\frac1{0.2}+\frac1{0.4}\right)$ , so $\frac{1.5}\mu=\frac76$ and $\mu=\frac97$ .

(B)

Topics:Thin lenses and lens maker's formula

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JEE Main 2022 · 28 Jul · Shift 2, Physics question 16