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JEE Main 2022 · 28 Jul · Shift 2, Physics question 6

Assume there are two identical simple pendulum clocks. Clock - 1 is placed on the earth and Clock - 2 is placed on a space station located at a height hh above the earth surface. Clock - 1 and Clock - 2 operate at time periods 4 s and 6 s respectively. Then the value of hh is -

(consider radius of earth RER_E = 6400 km and g on earth 10 m/s2^2)

Choose one option
Answer and worked solution

Official answer: C

T∝g−1/2T\propto g^{-1/2}. g′g=1636=(RR+h)2\frac{g'}g=\frac{16}{36}=\left(\frac R{R+h}\right)^2, so R+h=1.5RR+h=1.5R and h=3200h=3200 km.

(C)

Topics:Variation of gSimple and compound pendulum
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