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← JEE Main 2022 · 28 Jul · Shift 2
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JEE Main 2022 · 28 Jul · Shift 2, Physics question 1

Consider the efficiency of carnot's engine is given by η=αβsin⁡θlog⁡eβxkT\eta=\dfrac{\alpha\beta}{\sin\theta}\log_e\dfrac{\beta x}{kT}, where α\alpha and β\beta are constants. If T is temperature, k is Boltzmann constant, θ is angular displacement and xx has the dimensions of length. Then, choose the incorrect option :

Choose one option
Answer and worked solution

Official answer: D

Dimensionless pieces. η and the log are dimensionless, so βxkT\frac{\beta x}{kT} is too: β has the dimensions of energy per length, i.e. force. Then αβ\alpha\beta is dimensionless, so α=β−1\alpha=\beta^{-1}, which is length per energy.

Check. (A) is true. (B): α−1x\alpha^{-1}x is energy per length times length, energy, so true. (C): η−1sin⁡θ\eta^{-1}\sin\theta and αβ\alpha\beta are both dimensionless, true. (D) is false.

(D)