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← JEE Main 2022 · 28 Jul · Shift 2
MathematicsInteger+4 / -1Question 81 of 90

JEE Main 2022 · 28 Jul · Shift 2, Mathematics question 81

Let the coefficients of the middle terms in the expansion of (16+βx)4\left(\dfrac1{\sqrt6}+\beta x\right)^4, (1−3βx)2(1-3\beta x)^2 and (1−β2x)6\left(1-\dfrac\beta2x\right)^6, β>0\beta>0, respectively form the first three terms of an A.P. If d is the common difference of this A.P., then 50−2dβ250-\dfrac{2d}{\beta^2} is equal to ______.

Answer and worked solution

Official answer: 57

Coefficients β2\beta^2, −6β-6\beta, −52β3-\frac52\beta^3 in AP: 5β2−2β−24=05\beta^2-2\beta-24=0, so β=125\beta=\frac{12}5.

Difference d=−6β−β2d=-6\beta-\beta^2, so 2dβ2=−12β−2=−7\frac{2d}{\beta^2}=-\frac{12}\beta-2=-7.

Answer: 57