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← JEE Main 2022 · 28 Jul · Shift 2
ChemistryInteger+4 / -1Question 53 of 90

JEE Main 2022 · 28 Jul · Shift 2, Chemistry question 53

If the wavelength for an electron emitted from H-atom is 3.3×10−103.3\times10^{-10} m, then energy absorbed by the electron in its ground state compared to minimum energy required for its escape from the atom, is ______ times. (Nearest integer)

[Given : h = 6.626×10−346.626\times10^{-34} J s]

Mass of electron = 9.1×10−319.1\times10^{-31} kg

Answer and worked solution

Official answer: 2

Kinetic energy of the emitted electron h22mλ2=2.2×10−18\frac{h^2}{2m\lambda^2}=2.2\times10^{-18} J ≈13.9\approx13.9 eV.

Absorbed 13.6+13.9≈27.513.6+13.9\approx27.5 eV, about twice the 13.6 eV needed.

Answer: 2