JEE Main 2022 · 28 Jul · Shift 2 · Chemistry Q51

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ChemistryInteger+4 / -1Question 51 of 90

2L of 0.2M $\mathrm{H_2SO_4}$ is reacted with 2L of 0.1M NaOH solution, the molarity of the resulting product $\mathrm{Na_2SO_4}$ in the solution is ______ millimolar. (Nearest integer)

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Answer and worked solution

Official answer: 25

Amounts. 0.4 mol $\mathrm{H_2SO_4}$ and 0.2 mol NaOH give 0.1 mol $\mathrm{Na_2SO_4}$ in 4 L: 25 mM.

Answer: 25

Topics:Stoichiometry Concentration terms

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JEE Main 2022 · 28 Jul · Shift 2, Chemistry question 51